Data Sufficiency Questions for IBPS PO
Data Sufficiency Questions for IBPS PO 2017 Exam
The following questions are accompained by three statements (A), (B), and (C). You have to determine which statements(s) is/are sufficient/necessary to answer the questions (IBPS PO Mains 2017 Exam)
1. What is the value of a two-digit number in which digit at tens place is greater than digit at unit place?
A. The sum of the digits is 5.
B. The difference of the squares of the digits is 15.
C. The difference of their digits is 3.
(a) A and B together are sufficient
(b) B and C together are sufficient
(c) C and A together are sufficient
(d) Any one pair ofAandB,B and C or C and A is sufficient
(e) A, B and C together are necessary
2. What is the rate Of interest at which Binod has invested money?
A. The compound interest at this rate of ₹ 2500 in 2 yrs is equal to the simple interest in 3 yrs of ₹ 5150 at the same rate.
B. The total simple interest on an investment of ₹ 12000 for 3 yrs and ₹ 10000 for 5 yrs at this rate is ₹ 5160.
C. In 3 yrs ₹ 1500 at the same rate becomes ₹ 1725 by simple interest.
(a) Any of them
(b) A and either B or C
(c) Only C
(d) Only A and either B or C
(e) Any two of them
3. A person travels from X to Y and back again. How long will it take in travelling both the ways by bus ?
A. It takes 21 hours in travelling from X to Y by train and returning by bus.
B. The distance between X and Y is 648 km.
C. A person can save 3 hours if he travels both the ways by train as compared to travelling by bus on the one side and returning by train.
(a) Only A and C together
(b) Band either A or C
(c) Any two of them
(d) All statements are necessary
(e) Question can’t be answered even after using all the information
4. Find the number of days in which Q can do a job if P can do the same job in 8 days.
A. Q is 60% more efficient than P.
B. R P and Q together can do the job in 10/3 days.
C. Pis 75/2% less efficient than Q.
(a) Only A is sufficient
(b) Only B is sufficient
(c) Either A or B is sufficient
(d) Any of them
(e) A and C together are sufficient
5. What will be the cost of fencing a rectangular plot?
A. Cost of fencing a circular plot whose area is 616 m2 is ? 968.
B. Perimeter of the rectangular plot is 200 m.
C. Perimeter of the square whose length is equal to the breadth of the rectangular plot is 20 m.
(a) OnlyC
(b) A and C together
(c) A and B together
(d) A and either B or C
(e) Question can’t be answered even after using all the information
There are two quantities named I \ and II given below. Based on the given information, you have to determine the relation between the two quantities. You should use the given data to answers the questions. Give answer: (IBPS PO Mains 2017 Exam)
(a) Quantity -1 > Quantity – II
(b) Quantity -1 < Quantity – II
(c) Quantity -1 ≥ Quantity – II
(d) Quantity -1 ≤ Quantity – II
(e) Quantity -1 = Quantity – II
6. Quantity I: Profit percent when an article of cost price ₹ 160 is sold for ₹ 184.
Quantity II: When a person buys an article whose marked price is ₹ 2400 for ₹ 2016, then percentage discount availed by him.
7. Quantity I : If the speed of the boat in the direction of current is 13 km/hr and the speed of the current is 4 km/hr. What is the speed of the boat against current.
Quantity II: The downstream speed and upstream speed of the boat is 13 km/hr and 3 km/hr respectively. What is the speed of the stream
8. Quantity I: Present age of A and B are in the ratio of 4 : 5 respectively. Five years hence the ratio of their ages becomes 5 : 6 respectively. What is A’s present age
Quantity II: If the average age of A, B and C are 24 years, and the average of B and C is 20, then the age of A:
9. If X is earning 40% more than Z and Y is earning 3 5% more thanZ
Quantity I: If Z earning ? 17500, then X is earning .
Quantity II: If Z earning ? 20000, then Y is earning
10. Quantity I: The speed of the stream is 3 km/hr. A boat goes 30 km upstream and comes back again to the starting point
in 175 min. Then the speed of the boat in still water (in km/ hr):
Quantity II: A man in a car travels a certain distance in 20 min. He observes that he crossed 8 bus stops. If distance between two bus stops are 1000m, then the speed at which the car is travelling (in km/hr)
Data Sufficiency Questions for IBPS PO 2017 Answers
1. (d)
From A, x + y = 5
From B, x2 – y2 = 15
From C, x – y = 3
To determine the no. of any two statements are necessary
2. (a)
Let the rate of interest be r%
\(\mathrm { A } \quad 2500 \left[ \left( 1 + \frac { \mathrm { r } } { 100 } \right) ^ { 2 } – 1 \right] = 5150 \times \mathrm { r } \times \frac { 3 } { 100 }\)
\(\mathrm { B } \quad 12000 \times \mathrm { r } \times \frac { 3 } { 100 } + 10000 \times \mathrm { r } \times \frac { 5 } { 100 } = 5160\)
\(\mathrm { C } \quad \mathrm { r } = \frac { 1725 – 1500 } { 3 \times 1500 } \times 100 = 5 \%\)
Hence, any one of them is sufficient
3. (a)
From statement (A) and (C),
The person will take (21 – 3) 18 hrs, if he travels both ways by train. So it takes \(\left( \frac { 18 } { 2 } = 9 \right)\) hrs if he travels one way by train. Hence, he will take (9 + 3) 12 hrs if he travels one way by bus.
So, required time = 12 × 2 = 24hrs
4. (d)
Since each statement provides data related to another one so any of the three statements is sufficient
5. (c)
Statement (A) gives the cost of fencing one metre of the plot.
Combining this with statement (B), total cost of fencing can be determined.
6. (b)
Quantity – I
C.P. = 160
S.P. = 184
Profit = 184 – 160 = 24
Profit% \(= \frac { 24 } { 160 } \times 100\)
∴ Profit% = 15 %
Quantity – II
M.P. = 2400
S.P. = 2016
Discount = 2400 – 2016 = 384
Discount% \(= \frac { 384 } { 2400 } \times 100\)
Discount % = 16 %
∴ Quantity – I < Quantity – II
7. (e)
Quantity I = Quantity II or No relation can be established
Explanation:
Quantity I = 13 – 4 – 4 = 5 kmph
Quantity II = (13 – 3)/2 = 5km/hrs
8. (b)
∴ Quantity – I < Quantity – II
Quantity – I
Let the present age of A and B be 4x and 5x
\(\frac { 4 x + 5 } { 5 x + 5 } = \frac { 5 } { 6 }\)
∴ x = 5
∴ A’s present age = 20 yrs
Quantity – II
Average age of A, B and C = 24 years
Total = 24 × 3 = 72 years
Average age of B and C = 20 years
Total age of B and C = 20 × 2 = 40
Age of A = 72 – 40 = 32 years
9. (b)
Quantity I < Quantity II
Explanation:
X = 100 + 40/100 × 17500 = 24500
Y = 100 + 35/100 × 20000 = 27000
10. (e)
Explanation:
Quantity – I
Let speed of the Boat = x
Speed of the stream = 3 km/hr
\(\frac { 30 } { x – 3 } + \frac { 30 } { x + 3 } = \frac { 175 } { 60 }\)
\(\frac { 60 x } { x ^ { 2 } – 9 } = \frac { 35 } { 12 }\)
7x2 – 144x – 63 = 0
7x2 – 147x + 3x – 63 = 0
∴ x = 21
Quantity – II
Bus stops = 8
Distance between bus stops = 1 km
Total distance = 1 × 7 = 7 km
Let speed of car = x
Time = 20 min
\(\frac { 7 } { 20 } \times \frac { 60 } { 1 } = 21 \mathrm { km }\)
Hence, Quantity – II = Quantity – I
Data Sufficiency Questions for IBPS PO 2015 Exam
In these questions, a question is given followed by information in three statements. You have to consider the information in all the three statements and decide the information in which of the statement(s) is not necessarily required to answer the question and therefore can be dispensed with. Indicate your answer accordingly. (IBPS PO Main 2015)
1. How many students from Institute ‘A’ got placement?
I. Number of students studying in Institutes A & B are in the ratio of 3 : 4 respectively.
II. Number of students who got placement from Institute B is 120% of the number of students who got placement from Institute A.
III. 80% of the students studying in Institute B got placement.
(a) None of the statements can be dispensed with
(b) Only I
(c) Only II
(d) Anyone of the three
(e) Question cannot be answered even with the information in all three statements
2. What is the monthly income of Mr. X?
I. Mr. X spends 85% of his income on various items and remaining amount is saved.
II. Monthly saving of Mr. X are ₹ 4,500/.
III. Out of the total money spent by Mr. X in a month, one- fifth is spent on food and remaining amount of ₹ 20, 400 on other items.
(a) Only II
(b) Only III
(c) Only either II or III
(d) Question cannot be answered even with the information in all three statements
(e) None of these
3. What is Suchitra’s present age?
I. Suchitra’s present age is double the age of her son.
II. Ratio between present ages of Suchitra and her mother is 2 : 3 respectively.
III. Four years hence the ratio between Suchitra’s age and her son’s age will be 13 : 24 respectively.
(a) Only II
(b) Only III
(c) Either I or II only
(d) Either II or III only
(e) None of these
4. What is Neeta’s share in the profit earned at the end of 2 years in a joint business run by Neeta, Seeta and Geeta?
I. Neeta invested ₹ 85,000/ to start the business.
II. Seeta and Geeta joined Neeta’s business after six months investing amounts in the ratio of 3 : 5 respectively.
III. Total amount invested by Seeta and Geeta is ‘ 2.3 lakhs
(a) Only II
(b) Only III
(c) Only either II or III
(d) Information in all three statements is required for answering the question.
(e) Question cannot be answered even with the information in all three statements.
5. What is the labelled price of the article?
I. Cost price of the article is ₹ 500/.
II. Selling price after offering 5% discount on the labelled price is ₹ 608/.
III. Profit earned would have been 28% if no discount was offered.
(a) Only I
(b) Only III
(c) Only II & III
(d) Only I and III
(e) Only I and II
Data Sufficiency Questions for IBPS PO 2015 Answers
1. (e)
From statement I,
Let the number of students in the intitutes A and B be 3x and 4x respectively. However we get no conclusive answer by using data given in all the statements.
2. (c)
From statements I and II, Let Mr. X’s monthly income = ₹ x. Then
\(\frac { 15 \times x } { 100 } = 4500\)
\(\Rightarrow x = \frac { 4500 \times 100 } { 15 }\) = ₹ 30000
From statements I and III,
\(x \times \frac { 4 } { 5 } \times \frac { 85 } { 100 } = 20400\)
\(\Rightarrow x = \frac { 20400 \times 5 \times 100 } { 4 \times 85 }\) = ₹ 30000
3. (a)
From Statements I and III, Let Suchitra’s son’s present age be x years.
∴ Suchitra’s present age = 2x years
After 4 years,
\(\frac { 2 x + 4 } { x + 4 } = \frac { 13 } { 24 }\)
We can get the required answer by this relation.
So statement II is not required.
4. (d)
From all three statements, Seeta’s investment
= ₹ \(\left( \frac { 3 } { 8 } \times 2.5 \right)\)lakh = ₹ 93750
Geeta’s investment = ₹ 156250
Ratio of Neeta’s, Seeta’s and Geeta’s profit
= 85000 × 24 : 93750 × 18 : 156250 × 18
We can get the share of Neeta if total profit is given. So data given in all three statements is required to answer the question.
5. (d) Let the marked price of the article be ‘ x.
From statement II.
\(\frac { 95 \times x } { 100 } = 608\)
\(\Rightarrow x = \frac { 608 \times 100 } { 95 }\) = ₹ 640
From statements I and III,
\(Market\quad price\quad =\quad \frac { 128\times 500 }{ 100 } \) = ₹ 640
So statement II is sufficient to give the answer.
Data Sufficiency Questions for IBPS PO 2013 Exam
In each of the following questions, a question is followed by information given in three Statements I, II and III. You have to study the question along with the statements and decide the information given in which of the statement(s) is necessary to answer the question. (IBPS Bank PO/MT 2013)
1. In how many days 10 women can finish the work?
I. 10 men finish the work in 6 days. 3
II. 10 women and 10 men finish the work in 3 days.
III. If 10 men work 3 days and after that 10 women are deployed to work for men, the rest work is finished in 4 days.
(a) I and II
(b) Any two of three
(c) I and III
(d) II and III
(e) None of these
2. What is the present age of Sabir?
I. The present age of Sabir is half of his father’s age.
II. After five years the ratio of ages of Sabir and his father is 6 :11. ’
III. Sabir is younger to his brother by five years.
(a) I and II
(b) I and III
(c) II and III
(d) All of these
(e) Cannot be determined
3. What is two digit number?
I. The difference between the number and the number formed by interchanging the digit is 27.
II. The difference between two digits is 3.
III. The digit at unit’s place is less than that at ten place by 3.
(a) I and II
(b) I and either II or III
(c) I and III
(d) All of these
(e) None of these
4. What is the rate of interest Percent per annum?
I. An amount doubles itself in 5 yr on simple interest;
II. Difference between the compound interest and the simple interest earned on a certain amount in two years is ‘ 400.
III. Simple interest earned per annum is ‘ 2000.
(a) Only I
(b) II and III
(c) Any two of three
(d) I or II and III
(e) Only I or II and III
5. What is the cost of flooring the rectangular hall?
I. Length and the breadth of the hall are in the ratio of 3 : 2
II. Length of the hall is 48 m and cost of flooring is ‘ 850 per sq m.
III. Perimeter of the hall is 160 m and cost of flooring is ‘ 850 per sq m.
(a) I and II
(b) I and III
(c) Only III
(d) I and either II or III
(e) Any two of the three
Data Sufficiency Questions for IBPS PO 2013 Answers
1. (b)
women can finish the work in 1 day
\(= \frac { 7 } { 24 } – \frac { 1 } { 6 } = \frac { 7 – 4 } { 24 } = \frac { 1 } { 8 }\)
∴ 10 women can finish the work in 8 days.
From I and III,
Let 10 men can finish the work in x days and 10 women can finish the same work in y days.
Hence,
\(\frac { 1 } { x } + \frac { 1 } { y } = \frac { 7 } { 24 }\) —— (i)
and from III – II,
\(\frac { 3 } { x } + \frac { 4 } { y } = 1\) —— (ii)
from (i) & (ii)
y = 8 days
Again from I and III
\(\frac { 3 } { 6 } + \frac { 4 } { y } = 1 \Rightarrow y = 8\) days
2. (a)
From I, Let present age of Sabir be x yr and age of his father be 2x yr.
From I and II,
\(\frac { x + 5 } { 2 x + 5 } = \frac { 6 } { 11 } \Rightarrow 12 x + 30 = 11 x + 55\)
x = 25 yr
From I and II, age of Sabir = 25 yrs.
Hence, only from I & II, age of Sabir and his father can be obtained.
3. (e)
Let two digit number be 10x + y.
From I, either
\(x – y = \frac { 27 } { 9 } = 3 \Rightarrow y – x = \frac { 27 } { 9 } = 3\)
From II, x – y = 3 ⇒ y – x = 3
From III, x – y = 3
Hence, Even by (I) + (II) + (III) we cannot obtain the number.
4. (e)
From I, If P = 100
A = 200 and SI = 200 – 100 = 100
\(Rate\quad =\frac { { SI }\times 100 }{ { P }\times { T } } =\frac { 100\times 100 }{ 100\times 5 } =20%\)
From II and III,
\(Rate\quad =\frac { 400\times 100 }{ 2000\times 1 } =20%\)
Hence, either I alone or II + III will be sufficient.
5. (e)
From I and II.
Length = 3x = 48 m
∴ x = 16
Breadth = 2x = 32 m
Hence, Area of floor = 48 ×32
Cost of flooring = 48 × 32 × 850 = ₹ 1305600
From I and III, 2(l + b) = 160
⇒ 2(3x + 2x) = 160 ⇒ 10x = 160
∴ x = 16
∴Length = 3 × 16 = 48 m
Breadth = 2 × 16 = 32 m
Cost of flooring = (48 × 32) × 850 = ₹ 1305600
Similarly, from II and III, we can find I = 48 m and b = 32 m
and Total cost of flooring = ₹ 1305600
Leave a Reply