## Data Sufficiency Questions for IBPS SO

### Data Sufficiency Questions for IBPS SO 2015 Exam

**Each of the question below consists of a question and two statements marked A and B given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give answer.**

(a) if the data in statement A alone is sufficient to answer the question.

(b) if the data in statement B alone is sufficient to answer the question.

(c) if the data either in statement A alone or in statement B alone is sufficient to answer the question

(d) if the data given in both statements A and B together are not sufficient to answer the question.

(e) if the data in both statements A and B together are necessary to answer the question. **(IBPS SO 2015)**

**1.** What is the average age of children in the class?

A. Age of the teacher is as many yrs as the number of children.

B. Average age increased by 2 yr, if the teachers age is also included.

**2.** What is the average monthly income of a man if he saves ₹ 85000 during a year?

A. The average monthly expenditure for the first 4 months is ₹ 18000.

B. The average monthly expenditure for the next 8 months is ₹ 21000.

**3.** What is the salary of D, in a group A, B, C, D, E and F whose average salary is ₹ 45000?

A. Total salaries of A and F is ₹ 88900.

B. Total salaries of B and C is ₹ 95200.

**4.** What is the temperature on Thursday?

A. Average temperature for Monday, Tuesday and Wednesday is 34°^{C}.

B. Average temperature for Tuesday, Wednesday and Thursday is 38°^{C}.

**5.** The average of 12 numbers is 18. Find the new average when

A. The average of first 10 numbers is 20.

B. Each number is multiplied by 6.

**Data Sufficiency Questions for IBPS SO 2015 Answers**

**1.** (d)

Let the number of children be x ……… (i)

From statement A we get, teacher’s age = x

From statement B we get. Average age of (x + 1) persons (x + 2)

∴ Teacher’s age =(x + 2) (x + 1) = x^{2}

= x^{2} + 3x + 2 – x^{2}= 3x + 2 ………….. (ii)

From (i) and (ii) also we cannot find the average age of the children.

**2.** (e)

Savings of the man = ₹ 85000 ………(i)

From statement A we get

Monthly expenditure of the man for the first 4 months From statement B we get

= ₹ (18000 × 4) = ₹ 72000 ………….(ii)

= Monthly expenditure of the man for the next 8 months

= ₹ (21000 × 8) = ₹ 168000 …………(iii)

From (i), (ii) and (iii), we can find the income and his average monthly income.

**3.** (a)

A + B + C + D+E+F = (45000 × 6) = 270000 ……….(i)

From statement A, we get

A + F = 88900 ……….(ii)

From statement B, we get

B + C = 95200 …………(iii)

From (i), (ii) and (iii) also we cannot find D, because the salary of E is not given.

**4.** (d)

From A

Monday + Tuesday + Wednesday = 34 ^{0c}× 3 = 10^{0c}

From B

Tuesday + Wednesday + Thursday = 38^{0c} × 3 = 114^{0c}

Here, statement A and statement B together are not sufficient to answer the question.

**5.** (b)

From statement A, we get

Smn of the first 10 numbers = 10 × 20 = 200 ………(i)

Statement A is not sufficient to get the required answer.

From statement B, we get new average = (18 × 6) = 108 ……….(ii)

Statement B alone is sufficient to get the required answer.

### Data Sufficiency Questions for IBPS SO 2014 Exam

**Each of the questions below consists of a question and three statements denoted A, B and C are given below it. You have to study the questions and all the three statements and decide whether the question can be answered with any one or two of the statements or all the statements are required to answer the question. (IBPS SO 2014)**

**1.** What is R’s share of profit in a joint venture?

A. Q started business investing ₹ 80,000/-

B. R j oined him after 3 months.

C. P joined after 4 months with a capital of ₹ 1,20,000 and got ₹ 6,000 as his share of profit.

(a) Only A and C are required

(b) Only B and C are required

(c) All A, B and C together are required

(d) Even with all A, B and C the answer cannot be arrived

(e) None of these

**2.** What is the area of right angled triangle?

A. The perimeter of the triangle is 30 cm.

B. The ratio between the base and the height of the triangle is 5 : 12.

C. The area of the triangle is equal to the area of a rectangle of length 10 cms.

(a) Only B and C together are required

(b) Only A and B together are required

(c) Only either A or B and C together are required.

(d) Only A and C together are required

(e) None of these

**3.** What will be sum of two numbers?

A. Among the two numbers, the bigger number is greater than the smaller number by 6.

B. 40% of the smaller number is equal to 30% of the bigger number.

C. The ratio between half of the bigger number and \(\frac { 1 } { 3 } \mathrm { rd }\) of the smaller number is 2 : 1.

(a) Only B and C together are necessary

(b) Only A and B together are necessary

(c) Out of A, B and C any two together are necessary

(d) All three A, B and C together are necessary

(e) None of these

**4.** How much profit did Mahesh earn on the cost price of an article by selling it?

A. He got 15% discount on the marked price at the time of purchase.

B. He sold it for ₹ 3060.

C. He earned 2% profit on the marked price.

(a) Only A and B both together are necessary.

(b) Only B and C both together are necessary.

(c) Only A or C and B together are necessary.

(d) Even A, B and C all together are not sufficient to answer the question.

(e) All three A, B and C together are necessary.

**5.** How much marks did Arun secure in English?

A. The average marks obtained by Arun in four subjects included English is 60.

B. The total marks obtained by him in English and Mathematics together is 170.

C. The total marks obtained by him in Mathematics and Science together is 180.

(a) All three A, B and C together are necessary.

(b) Only A and B together are necessary

(c) Only B and C together are necessary.

(d) Only A and C together are necessary.

(e) None of these

**Data Sufficiency Questions for IBPS SO 2014 Answers**

**1.** (d)

The question cannot be answered because R’s share in investment is not given.

**2.** (b)

A. Hypotenuse \(= \sqrt { 5 ^ { 2 } + 12 ^ { 2 } } = \sqrt { 25 + 144 } = \sqrt { 169 } = 13\)

Base : Height : Hypotenuse = 5 : 12 : 13

B. Base + Height + Hypotenuse = 30 cm

∴ \(\text { Base } = \frac { 5 } { 5 + 12 + 13 } \times 30 = 5 \mathrm { cm }\)

\(\text { Height } = \frac { 12 } { 5 + 12 + 13 } \times 30 = 12 \mathrm { cm }\)

\(\text { Area } = \frac { 1 } { 2 } \times \text { base } \times \text { height } = \frac { 1 } { 2 } \times 5 \times 12 = 30 \mathrm { cm } ^ { 2 }\)

**3.** (b)

A. x – y = 6

B. 0.4y = 0.3x

\(\frac { x } { y } = \frac { 4 } { 3 } ; \quad C \cdot \frac { x } { 2 } \cdot \frac { y } { 3 } = 2 : 1\)

\(\frac { x } { y } \times \frac { 3 } { 2 } = \frac { 2 } { 1 } \Rightarrow \frac { x } { y } = \frac { 4 } { 3 }\)

B and C give the same expression / information and hence are equivalent.

\(\mathrm { x } = \frac { 4 } { 3 } \mathrm { y } \Rightarrow \mathrm { x } – \mathrm { y } = 6\)

\(\frac { 4 } { 3 } y – y = 6 \Rightarrow \frac { y } { 3 } = 6\)

\(y = 18 \text { and } x = \frac { 4 } { 3 } \times 18 = 24\)

**4.** (e)

Let the marked price be ₹ x

A. cost price = (1 – 0.15)x = ₹ 0.85x

B. S.P. = ₹ 3060

C. Profit = 2% of x = 0.02x

Profit earned on the cost price \(= \frac { 0.02 \mathrm { x } } { 0.85 \mathrm { x } } \times 100 \approx 2.35 \%\)

0.02x = 3060 – 0.85x

\(0.87 x = 3060 \text { or } x = \frac { 3060 } { 0.87 }\)

Actual profit = 0.02x

\(= 0.02 \times \frac { 3060 } { 0.87 }\) = ₹ 70.34

**5.** (e)

A. Total marks in 4 subjects including English = 4 × 60 = 240

B. Total marks in English and Maths = 170

C. Total marks in Maths and Science = 180

The question can’t be answered because nothing has been said about the marks in the fourth subject. Also, there are four unknowns but only three equations can be formed with given data.

## Leave a Reply