## Data Sufficiency Questions for SBI Clerk

### Data Sufficiency Questions for SBI Clerk 2016 Exam

**In each of the given questions, one questions and two statements numbered I and II are given. You have to decide whether the data given in both statements are sufficient to answer the question or not. Read both the statements and give answer (SBI Clerk 2016)**

(a) if the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.

(b) if the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.

(c) if the data either in statement I alone or in statement II alone are sufficient to answer the question.

(d) if the data in both statements I and II together are not sufficient to answer the question.

(e) if the data in both the statements I and II together are necessary to answer the question.

**1. **By how many years is Rasika younger than her brother Sunil?

(I). Ratio between Rasika’s present age and Sunil’s age after four years is 5 : 7 respectively

(II). Ratio between Rasika’s age four years ago and Sunil’s present age is 2 : 3 respectively

**2. **What is the quantity of milk in 80 litres of mixture of milk and water?

(I). If 8 litres of mixture is replaced by equal quantity of water the ratio of milk and water in the mixture becomes 27 : 13 respectively

(II). If 16 litres of mixture is replaced by equal quantity of milk, the ratio of milk and water in the mixture becomes 4 : 1 respectively

**3.** Neeraj invested certain amount in schemes A and B for 2 years in the ratio of 3 : 5 respectively. The schemes A and B offer compound interest compound annually and simple interest respectively. What is the amount invested in scheme A?

(I). Rate of interest offered by scheme A is 20% per annum and the rate of interest offered by scheme B is 25% less than that offered by scheme A.

(II). Amount of interest accrued from scheme B is more than the amount of interest accrued from scheme A by ₹ 900.

**4. **Two friends X and Y start running towards each other at the same time from points A and B respectively and meet after 135 minutes. At what speed is X running?

(I). Point B is 45 km away from point A and speed of X is 150% of the speed of Y.

(II). Distance covered by Y was 18 km.

**5. **What is the cost of painting two adjacent walls of a hall having no door or window at ₹ 450 per m^{2} ?

(I). Length and breadth are in the ratio of 3 : 2 respectively.

(II). Perimeter of the hall is 50 m and height is one-fourth of the perimeter.

### Data Sufficiency Questions for SBI Clerk 2016 Answers

**1.**

**2. **By statement – I

M : W = 27 : 13

So, in 80 litres of mixture contain

Quantity of milk [latex]= \frac { 27 } { 40 } \times 80 = 54[/latex] litres

Water [latex]= \frac { 13 } { 40 } \times 80 = 26[latex] litres

By statement – II

If 16 litres of mixture replaced by equal quantity of milk. then in new mixture.

Quantity of milk [latex]= \frac { 4 } { 5 } \times 80 = 64[/latex] litres

Quantity of water [latex]= \frac { 1 } { 5 } \times 80 = 16[/latex] litres

Again by statement -I Before mixing water.

Milk is litres and water is 18 litres

Statement – II before mixing milk 48 litres and water is 16 litres

Ratio of milk to water in mixture. = 3 : 1

Quantity of milk [latex]= \frac { 3 } { 4 } \times 80 = 60[/latex] litres

Concept Ratio of milk to water is always same in the mixture. It doesn’t depend on Quantity of mixture drawn.

**3.**

**4.**

Total time taken = 2 h 15 min

Let speed of y be S km/h

Speed of x be 1.5 S km/h.

Total time taken [latex]= \frac { \text { Total distance } } { \text { Total speed } }[/latex]

[latex]2 \frac { 1 } { 4 } = \frac { 45 } { 2.5 S } \Rightarrow \frac { 9 } { 4 } = \frac { 45 } { 2.5 \mathrm { S } } \Rightarrow = \mathrm { S } = \frac { 45 } { 2.5 } \times \frac { 4 } { 9 }[/latex]

∴ Speed of x = 1.5 \mathrm { S } = 1.5 \frac { 45 } { 25 } \times \frac { 4 } { 9 } = 12 \mathrm { km } / \mathrm { h }

**5. **(e) 22.5 15

Height [latex]= 50 \times \frac { 1 } { 4 } = 12.5[/latex]

Perimeter = 2 (3x + 2x) = 50

⇒ x = 5

So, area of two any adjacant walls = b× h + l × h = h (l + b)

Total cost of painting on wall = 12.5 × 25 × 450

= ₹ 140625

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