## problems on Trains formula

**km/hr to m/s conversion:**

**m/s to km/hr conversion:**

**Formulas for finding Speed, Time and Distance**

- When train passes a telegraph post or a standing man it should travel the length equal to the length of the train.
- When a train passes a platform or crosses a bridge it should travel the length equal to the sum of the lengths of train and platform or bridge both.
- When two trains are moving in opposite directions their speeds should be added to find the relative speed.
- When two trains are moving in the same direction the relative speed will be the difference of their speeds.
- Two trains are moving in the same direction at x km/hr and y km/hr (where x > y). If the faster train crosses a man in the slower train in ‘t’ seconds, then the length of the faster train is given by

- A train running at x km/hr takes t
_{1}seconds to pass a platform. Next it takes t_{2}seconds to pass a man walking at y km/hr in the opposite direction, then the length of the train is [(5/18)(x+y)k_{2}]meters and that of the plat-form is [(5/18)[x(t_{1-}t_{2})k_{2}]]meters. - Two trains are moving in opposite directions at x km/hr and y km/hr (where x >y), if the faster train crosses a man in the slower train in t seconds, then the length of the faster train is given by

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